https://leetcode.com/problems/compare-strings-by-frequency-of-the-smallest-character/
Let's define a function f(s)
over a non-empty string s
, which calculates the frequency of the smallest character in s
. For example, if s = "dcce"
then f(s) = 2
because the smallest character is "c"
and its frequency is 2.
Now, given string arrays queries
and words
, return an integer array answer
, where each answer[i]
is the number of words such that f(queries[i])
< f(W)
, where W
is a word in words
.
Example 1:
Input: queries = ["cbd"], words = ["zaaaz"] Output: [1] Explanation: On the first query we have f("cbd") = 1, f("zaaaz") = 3 so f("cbd") < f("zaaaz").