https://leetcode.com/problems/pairs-of-songs-with-total-durations-divisible-by-60/

In a list of songs, the `i`

-th song has a duration of `time[i]`

seconds.

Return the number of pairs of songs for which their total duration in seconds is divisible by `60`

. Formally, we want the number of indices `i < j`

with `(time[i] + time[j]) % 60 == 0`

.

**Example 1:**

Input:[30,20,150,100,40]Output:3Explanation:Three pairs have a total duration divisible by 60: (time[0] = 30, time[2] = 150): total duration 180 (time[1] = 20, time[3] = 100): total duration 120 (time[1] = 20, time[4] = 40): total duration 60