Leetcode - spiral-matrix
Leetcode - most-common-word

Leetcode - Spiral Matrix II

violet posted @ Mar 03, 2020 10:12:33 AM in 算法 with tags Algorithm array ruby Golang , 281 阅读

Given a positive integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.

Example:

Input: 3
Output:
[
 [ 1, 2, 3 ],
 [ 8, 9, 4 ],
 [ 7, 6, 5 ]
]

 

Loop  4 directions and fill it.

func generateMatrix(n int) [][]int {
    directions := []string{"right", "down", "left", "up"}
    result := make([][]int, n)
    for i := 0; i < n; i++ {
        result[i] = make([]int, n)
    }
    rowStart := 0
    rowEnd := n
    columnStart := 0
    columnEnd := n
    visited := 1
    for (visited - 1) != (n*n) {
        for _, d := range directions {
            if d == "right" {
                for i := columnStart; i < columnEnd; i++ {
                    result[rowStart][i] = visited
                    visited++
                }
                rowStart++
            }
            if d == "down" {
                for i := rowStart; i < rowEnd; i++ {
                    result[i][columnEnd-1] = visited
                    visited++
                }
                columnEnd--
            }
            if d == "left" {
                for i := columnEnd - 1; i >= columnStart; i--{
                    result[rowEnd - 1][i] = visited
                    visited++
                }
                rowEnd--
            }
            if d == "up" {
                for i := rowEnd - 1; i >= rowStart; i-- {
                    result[i][columnStart] = visited
                    visited++
                }
                columnStart++
            }
            if (rowStart == rowEnd && columnStart == columnEnd) || (visited-1 == n*n) {
                break
            }
        }
        if rowStart == rowEnd && columnStart == columnEnd {
            break
        }
    }
    
    return result
}

 

# @param {Integer} n
# @return {Integer[][]}
def generate_matrix(n)
    visited = 1
    row_start = 0
    row_end = n - 1
    column_start = 0
    column_end = n - 1
    directions = ["right", "down", "left", "up"]
    grid = Array.new(n){Array.new(n, 0)}

    while visited - 1 != n * n
        directions.each do |d|
            if d == "right"
                for i in column_start..column_end
                    grid[row_start][i] = visited
                    visited += 1
                end
                row_start += 1
            end
            if d == "down"
                for i in row_start..row_end
                    grid[i][column_end] = visited
                    visited += 1
                end
                column_end -= 1
            end
            
            if d == "left"
                i = column_end
                while i >= column_start
                    grid[row_end][i] = visited
                    visited += 1
                    i -= 1
                end
                row_end -= 1
            end
            
            if d == "up"
                i = row_end
                while i >= row_start
                    grid[i][column_start] = visited
                    visited += 1
                    i -= 1
                end
                column_start += 1
            end

            break if  visited - 1 == n*n      
        end
        break if visited - 1 == n*n
        
    end

    return grid
end
modelpapers2020.in 说:
May 03, 2023 09:24:20 PM

Board Model Paper 2023 Aspirants who had Registered for the Board 12th Class Exam can Download the Previous Paper When Board Announces the Dates to Download the Question Paper. modelpapers2020.in Board Question Papers will be Provided Very Soon Through Online Mode and all the Applicants Should Visit the Official Page Regularly for More Information Regarding Previous Paper, Examination Date. Check the Below Provided Details for More Information About the Board Model Paper.


登录 *


loading captcha image...
(输入验证码)
or Ctrl+Enter