Geeks4Geeks - check-if-the-given-binary-tree-have-a-subtree-with-equal-no-of-1s-and-0s
Leetcode - how-many-numbers-are-smaller-than-the-current-number

Leetcode - path-sum

violet posted @ Mar 06, 2020 08:39:52 AM in 算法 with tags Algorithm tree DFS Golang Ruby , 393 阅读

https://leetcode.com/problems/path-sum/

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

Note: A leaf is a node with no children.

Example:

Given the below binary tree and sum = 22,

      5
     / \
    4   8
   /   / \
  11  13  4
 /  \      \
7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

Just think about the sum seems a bit difficult. It can be treated as if there is a path containing nodes and can be subbed by sum and then getting 0.

func hasPathSum(root *TreeNode, sum int) bool {
    if root == nil {
        return false
    }
    if root.Val == sum {
        return true
    }
    return hasPathSum(root.Left, sum - root.Val) || hasPathSum(root.Right, sum - root.Val)
}
def has_path_sum(root, sum)
    if root == nil
        return false
    end
    if root.right == nil && root.left == nil && root.val == sum
        return true
    end
    return has_path_sum(root.left, sum - root.val) || has_path_sum(root.right, sum - root.val)
end

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