Leetcode - Trapping Rain Water
https://leetcode.com/problems/trapping-rain-water/
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.
The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Thanks Marcos for contributing this image!
Example:
Input: [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6
Just track every point maxLeft and maxRight. And if the current value is smaller than maxLeft/maxRight, add maxLeft - currentValue into result.
func trap(height []int) int {
left := 0
right := len(height)-1
maxLeft := 0
maxRight := 0
result := 0
for left <= right {
if height[left] <= height[right] {
if maxLeft < height[left] {
maxLeft = height[left]
} else {
result += maxLeft - height[left]
}
left++
} else {
if maxRight < height[right] {
maxRight = height[right]
} else {
result += maxRight - height[right]
}
right--
}
}
return result
}
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