Leetcode - Compare Strings by Frequency of the Smallest Character

Leetcode - Counting Elements

violet posted @ 5 年前 in 算法 with tags Algorithm Golang count sort , 555 阅读

Given an integer array arr, count element x such that x + 1 is also in arr.

If there're duplicates in arr, count them seperately.

Example 1:

Input: arr = [1,2,3]
Output: 2
Explanation: 1 and 2 are counted cause 2 and 3 are in arr.

func countElements(arr []int) int {
    count := make([]int, 1001)
    for _, a := range arr {
        count[a]++
    }
    result := 0
    for i := 0; i < len(count)-1; i++ {
        if count[i] > 0 && count[i+1] > 0 {
            result += count[i]
        }
    }
    return result
}