Leetcode - Design Compressed String Iterator
Leetcode - Range Addition

Leetcode - Find Words That Can Be Formed by Characters

violet posted @ May 08, 2020 07:11:48 AM in 算法 with tags Algorithm Golang array , 197 阅读

https://leetcode.com/problems/find-words-that-can-be-formed-by-characters/

You are given an array of strings words and a string chars.

A string is good if it can be formed by characters from chars (each character can only be used once).

Return the sum of lengths of all good strings in words.

 

Example 1:

Input: words = ["cat","bt","hat","tree"], chars = "atach"
Output: 6
Explanation: 
The strings that can be formed are "cat" and "hat" so the answer is 3 + 3 = 6.

Example 2:

Input: words = ["hello","world","leetcode"], chars = "welldonehoneyr"
Output: 10
Explanation: 
The strings that can be formed are "hello" and "world" so the answer is 5 + 5 = 10.

 

func countCharacters(words []string, chars string) int {
    charCount := getCount(chars)
    result := 0
    for _, w := range words {
        wCount := getCount(w)
        found := true
        for i := 0; i < 26; i++ {
            if wCount[i] > charCount[i] {
                found = false
                break
            }
        }
        if found {
            result += len(w)
        }
    }
    return result
}

func getCount(w string) []int {
    count := make([]int, 26)
    for i := 0; i < len(w); i++ {
        count[w[i]- 'a']++
    }
    return count
}

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