Leetcode - Third Maximum Number
https://leetcode.com/problems/third-maximum-number/
Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n).
Example 1:
Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1.
func thirdMax(nums []int) int {
if len(nums) == 1 {
return nums[0]
}
if len(nums) == 2 {
if nums[0] > nums[1] {
return nums[0]
}
return nums[1]
}
first := math.MinInt64
second := math.MinInt64
third := math.MinInt64
for i := 0; i < len(nums); i++ {
if nums[i] == first || nums[i] == second || nums[i] == third {
continue
}
if first == math.MinInt32 || nums[i] > first {
third = second
second = first
first = nums[i]
} else if second == math.MinInt32 || nums[i] > second {
third = second
second = nums[i]
} else if third == math.MinInt32 || nums[i] > third {
third = nums[i]
}
}
fmt.Println("first: ", first)
fmt.Println("second: ", second)
fmt.Println("third: ", third)
if third == math.MinInt64 {
return first
}
return third
}
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